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Post by clyevo on May 4, 2015 15:26:36 GMT
Yes to minimize acc/dec ramp we need more torque right?
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Post by vicpopo on May 4, 2015 15:51:10 GMT
I don't know if you need more torque ! But more torque is always a good thing ! ;-) But it's important to the goal to reproduce the maximum of game information! It depends also from the complete loop which convert game informations to the real setpoints for your sim
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Post by clyevo on May 6, 2015 8:51:52 GMT
I just would like to share this link machinedesign.com/motorsdrives/top-10-tips-working-gearmotorsit explains most of the thing u need to know about choosing power vs payload and "service factor" which is important in the application of motion simulator that involves lots of direction changes with high inertia from what i read it is better to use better quality high torque motors (higher pole counts) and better service factor value (higher quality motor/gearbox) and not just plain simple: the bigger the better route
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Post by riton39 on Aug 28, 2015 21:48:58 GMT
Yes to minimize acc/dec ramp we need more torque right? yes, more power you have, the more you can decrease the ramp, but within the limits of errors. it is a general rule. with power you have more torque, and therefore more ability to handle the load. over the ramp is low get more small effects. it's nice to have the vector control, but it can be also interesting to test in U / F mode. vector control solicits more engines are always magnetized and the couple is still important. it takes the power or you may also have errors. it is important not to take too limiting engine power.
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johann
Junior Member
Posts: 57
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Post by johann on Dec 13, 2016 12:50:15 GMT
Hi everybody I’m new in this forum. I’m not an engineer but I’m a FSX enthusiast and so I started to build up my one 6 DOF simulator for it. Therefor I contacted Thanos and ordered his AMC1280USB board. He also told me how to calculate the motor force to carry the payload. The formula from him is the following: You multiply the Nm value by the reduction of the gearbox and divide to how much if the arm length related to the 1 meter value of the torque.I’ve used this formula for a couple of motors, see attached picture. Thanos has at the moment not so much time to answer all my stupid beginner questions and he recommended me to ask you inside this forum. My first question is: Did I do the calculation right? The result is in the line above the cost line. If not what is the right one? Thanks for your help Johann
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Post by tronicgr on Dec 16, 2016 17:59:51 GMT
Hi everybody I’m new in this forum. I’m not an engineer but I’m a FSX enthusiast and so I started to build up my one 6 DOF simulator for it. Therefor I contacted Thanos and ordered his AMC1280USB board. He also told me how to calculate the motor force to carry the payload. The formula from him is the following: You multiply the Nm value by the reduction of the gearbox and divide to how much if the arm length related to the 1 meter value of the torque.I’ve used this formula for a couple of motors, see attached picture. Thanos has at the moment not so much time to answer all my stupid beginner questions and he recommended me to ask you inside this forum. My first question is: Did I do the calculation right? The result is in the line above the cost line. If not what is the right one? Thanks for your help Johann Hi Johann, Send me this spreadsheet, I'll check it, and perhaps I can add a few things to it. Thanks Thanos
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johann
Junior Member
Posts: 57
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Post by johann on Dec 17, 2016 8:01:48 GMT
Hi Thanos,
I sent you the list via mail. When you add the missing information you can put it to the forum here if you want. Thank you very much for your help and your explanations for the VFD inverter WS200_004SF too.
Johann
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